BODMAS

Order of Operation 
While solving questions involving mathematical operations involving addition, subtraction, multiplication and division we follow a particular order while performing a calculation. To perform calculations we follow BODMAS.

BODMAS stands for
B = Bracket
O = of
D = Division
M= Multiplication
A = Addition
S= Subtraction
Let us see examples based on this
Example 1:

What is the value of N= {(4 +5)of4}/3 + 2 ?
Solution:
We will solve bracket first
{(9) x 4}/3 + 2
= 12 + 2
= 14

Example 2:
What is the value of N= {(12÷4× 2 +5) of4}/2−1 ?Solution:We will solve terms inside bracket first={(12÷4× 2 +5) of4}/2−1={(3 ×2 +5) of4}/2−1 (We divided 12 and 4 first)={(6 +5) of4}/2−1 (We multiplied 3 and 2)={(11) of4}/2−1 (We added 6 and 5)={44}/2−1 (We wrote 11 of 4)= 22−1(We divided 44 and 2)=21(We subtracted 1 from 22)What is the value of N= {(12÷4× 2 +5) of4}/2−1 ?Solution:We will solve terms inside bracket first={(12÷4× 2 +5) of4}/2−1={(3 ×2 +5) of4}/2−1 (We divided 12 and 4 first)={(6 +5) of4}/2−1 (We multiplied 3 and 2)={(11) of4}/2−1 (We added 6 and 5)={44}/2−1 (We wrote 11 of 4)= 22−1(We divided 44 and 2)=21(We subtracted 1 from 22)

Example 3:
What is the value of N = {(18 ÷ 3 × 2 + 1) of 8}/2 + 5?
Solution:
We will solve the terms inside the bracket first
{(18 ÷ 3 × 2 + 1) of 8}/2 + 5
= {6 × 2 + 1) of 8}/2 + 5   (We divided 18 and 3)
= {(12 + 1) of 8}/2 + 5      (We multiplied 6 and 2)
= {13 of 8}/ 2 + 5              (We added 12 and 1)
= (104)/2 + 5                      (We wrote 13 of 8)
= 52 + 5                              (We divide 104 and 2)
= 57                                    (We added 52 and 5)

Example4:What is the value of N= {(9 + 8÷ 2× 3) of8}/2 + 3 ?Solution:We will solve terms inside bracket first{(9 +8÷ 2 ×3) of8}/2 + 3={(9 + 4× 3) of8}/2 + 3(We divided 8 and 2 first)= {(9 + 12) of8}/2 + 3(We multiplied 3 and 4)= {(21) of8}/2 + 3(We added 9 and 12)= {168}/2 + 3(We wrote 21 of 8)= 84+ 3(We divided 168 and 2)= 87(We added 3 in 84 )